What is the domain of \sqrt[4]{x^4-81} ?

The domain of \sqrt[4]{x^4-81} is x = 3

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domain of \sqrt[4]{x^4-81}

domain

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

e^{2 x - 1}

f (x) = x^{2} + y^{2} = 1

y = (x - 2)^{3}

x (x + 13) + 40

2 x - 1

What is the domain of \sqrt[4]{x^4-81} ?
The domain of \sqrt[4]{x^4-81} is x<=-3\lor x>= 3