What is the range of sqrt((x-1)^2) ?

The range of sqrt((x-1)^2) is f(x)>= 0

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range of sqrt((x-1)^2)

range

(x - 1)^{2}

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

(x - 1)^{2} : - \infty < x < \infty

Simplify

(x - 1)^{2} : ∣ x - 1 ∣

Extreme Points of

∣ x - 1 ∣ :

Minimum

(1, 0)

Find the range for the interval

- \infty < x < \infty : 0 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 0

y = - x + 7

f (x) = x^{2} e^{x} - 6

f (x) = 3 x - 5 y = - 15

3 - \frac{1}{2} x

- 3 x - y = - 2