What is the inverse of f(x)=x^2-2x-8 ?

The inverse of f(x)=x^2-2x-8 is 1+sqrt(x+9),1-sqrt(x+9)

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inverse of f(x)=x^2-2x-8

inverse

f (x) = x^{2} - 2 x - 8

1 + x + 9, 1 - x + 9

Solution steps

y = x^{2} - 2 x - 8

Replace

x

with

y

x = y^{2} - 2 y - 8

Solve for

y, x = y^{2} - 2 y - 8

1 + x + 9, 1 - x + 9

x - 8 = 0

f (x) = 5 - x

f (x) = ∣ x ∣ + 2

f (x) = 7 x^{3} + 2

\frac{7}{t}

What is the inverse of f(x)=x^2-2x-8 ?
The inverse of f(x)=x^2-2x-8 is 1+sqrt(x+9),1-sqrt(x+9)