What is the inverse of f(x)=(x-2)^2,x<= 2 ?

The inverse of f(x)=(x-2)^2,x<= 2 is sqrt(x)+2,-sqrt(x)+2

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inverse of f(x)=(x-2)^2,x<= 2

inverse

f (x) = (x - 2)^{2}, x \leq 2

x + 2, - x + 2

Solution steps

y = (x - 2)^{2}

Replace

x

with

y

x = (y - 2)^{2}

Solve for

y, x = (y - 2)^{2}

x + 2, - x + 2

f (x) = 7 + (6 + x)^{\frac{1}{2}}

\frac{x ^{2}}{x ^{2} - 4}

f (x) = \frac{45 x ^{2}}{25 x}

3 cos^{2} (x)

f (x) = \frac{5}{4} x - 10

What is the inverse of f(x)=(x-2)^2,x<= 2 ?
The inverse of f(x)=(x-2)^2,x<= 2 is sqrt(x)+2,-sqrt(x)+2