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Popular >

midpoint (2,-8),(7,-4)

Solution

midpoint

(2, - 8), (7, - 4)

Solution

(\frac{9}{2}, - 6)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 8), (x_{2}, y_{2}) = (7, - 4)

= (\frac{7 + 2}{2}, \frac{- 4 - 8}{2})

Refine

= (\frac{9}{2}, - 6)

Popular Examples

domain of f(x)=(|x|)/x domain

f (x) = \frac{∣ x ∣}{x}

asymptotes of (x^2+x-12)/(x-3)asymptotes

\frac{x ^{2} + x - 12}{x - 3}

intercepts of (2x)/(x^2-1)intercepts

\frac{2 x}{x ^{2} - 1}

inverse of f(x)=-6x-4 inverse

f (x) = - 6 x - 4

range of f(x)=|x^2-4x|-1 range

f (x) = x^{2} - 4 x - 1

Frequently Asked Questions (FAQ)

What is the midpoint (2,-8),(7,-4) ?
The midpoint (2,-8),(7,-4) is (9/2 ,-6)