What is the inverse of f(x)=\sqrt[5]{(x+3)/2} ?

The inverse of f(x)=\sqrt[5]{(x+3)/2} is 2x^5-3

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inverse of f(x)=\sqrt[5]{(x+3)/2}

inverse

2 x^{5} - 3

Solution steps

Replace

x

with

y

Solve for

2 x^{5} - 3

x ln (x)

f (x) = x^{2} + 2 x - 5

(- 1, - 8), (8, 0)

f (x) = \frac{2 ( x + 2 )}{x ^{2}}

f (x) = 2 x^{3} + 9 x^{2} + 12 x

What is the inverse of f(x)=\sqrt[5]{(x+3)/2} ?
The inverse of f(x)=\sqrt[5]{(x+3)/2} is 2x^5-3