What is the range of y=sqrt(x-5)-sqrt(x+5) ?

The range of y=sqrt(x-5)-sqrt(x+5) is -sqrt(10)<= f(x)<0

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range of y=sqrt(x-5)-sqrt(x+5)

range

y = x - 5 - x + 5

- 10 \leq f (x) < 0

Interval Notation

[- 10, 0)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x - 5 - x + 5 : x \geq 5

Extreme Points of

x - 5 - x + 5 :

Minimum

(5, - 10)

Find the range for the interval

5 \leq x < \infty : - 10 \leq f (x) < 0

Combine the ranges of all domain intervals to obtain the function range

- 10 \leq f (x) < 0

- \frac{2}{( x - 3 ) ^{2}}

f (x) = 5^{3 x + 1}

5 - x

f (x) = \frac{x - 7}{x ^{2} + 7}

f (x) = \frac{2 x}{- 4 x - 20}

What is the range of y=sqrt(x-5)-sqrt(x+5) ?
The range of y=sqrt(x-5)-sqrt(x+5) is -sqrt(10)<= f(x)<0