What is the inverse of 4x-9x^{1/2} ?

The inverse of 4x-9x^{1/2} is (8x+81+9(16x+81)^{1/2})/(32),(8x+81-9(16x+81)^{1/2})/(32)

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inverse of 4x-9x^{1/2}

inverse

4 x - 9 x^{\frac{1}{2}}

\frac{8 x + 81 + 9 ( 16 x + 81 ) ^{\frac{1}{2}}}{32}, \frac{8 x + 81 - 9 ( 16 x + 81 ) ^{\frac{1}{2}}}{32}

Solution steps

y = 4 x - 9 x^{\frac{1}{2}}

Replace

x

with

y

x = 4 y - 9 y^{\frac{1}{2}}

Solve for

y, x = 4 y - 9 y^{\frac{1}{2}}

\frac{8 x + 81 + 9 ( 16 x + 81 ) ^{\frac{1}{2}}}{32}, \frac{8 x + 81 - 9 ( 16 x + 81 ) ^{\frac{1}{2}}}{32}

\frac{1}{2 6 - x}

2 x + 3 - 5

f (x) = 4 + lo g_{5} (x - 2)

f (x) = \frac{1}{x - 3}

f (x) = x^{2} + x + 1

What is the inverse of 4x-9x^{1/2} ?
The inverse of 4x-9x^{1/2} is (8x+81+9(16x+81)^{1/2})/(32),(8x+81-9(16x+81)^{1/2})/(32)