What is the domain of f(x)=sqrt(sin(x)) ?

The domain of f(x)=sqrt(sin(x)) is 2pin<= x<= pi+2pin

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domain of f(x)=sqrt(sin(x))

domain

f (x) = sin (x)

2 πn \leq x \leq π + 2 πn

Interval Notation

[2 πn, π + 2 πn]

Solution steps

Find non-negative values for radicals:

2 πn \leq x \leq π + 2 πn

The function domain

2 πn \leq x \leq π + 2 πn

ln (X + 8)

- 2 cos (5 x)

x + 3 y = - 3

f (x) = 1.05 x

\frac{x ^{2} - 8 x + 12}{x ^{2} - 2 x - 24}

What is the domain of f(x)=sqrt(sin(x)) ?
The domain of f(x)=sqrt(sin(x)) is 2pin<= x<= pi+2pin