What is the asymptotes of f(x)= 2/(x^2+3x) ?

The asymptotes of f(x)= 2/(x^2+3x) is Vertical: x=-3,x=0,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)= 2/(x^2+3x)

asymptotes

f (x) = \frac{2}{x ^{2} + 3 x}

Vertical : x = - 3, x = 0, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2}{x ^{2} + 3 x} : x = - 3, x = 0

Horizontal Asymptotes of

\frac{2}{x ^{2} + 3 x} : y = 0

Slant Asymptotes of

\frac{2}{x ^{2} + 3 x} :

None

Vertical : x = - 3, x = 0, Horizontal : y = 0

f (x) = \frac{( 5 x - 5 )}{( x ^{2} - 1 )}

f (x) = x^{2} + 3 x + \frac{1}{4}

x + 2

x + 4 - \frac{1 - x}{x}

f (x) = \frac{8}{x - 6}

What is the asymptotes of f(x)= 2/(x^2+3x) ?
The asymptotes of f(x)= 2/(x^2+3x) is Vertical: x=-3,x=0,Horizontal: y=0