What is the critical 6x^2-4x^4 ?

The critical 6x^2-4x^4 is x=-(sqrt(3))/2 ,x=0,x=(sqrt(3))/2

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critical 6x^2-4x^4

critical points

6 x^{2} - 4 x^{4}

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

Solution steps

6 x^{2} - 4 x^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

Identify critical points not in

f (x)

domain

Domain of

6 x^{2} - 4 x^{4} : - \infty < x < \infty

All critical points are in domain

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

f (x) = 4 x^{2} - 6 x

4 y + 12 x = 28, (- 7, - 4)

f (x) = 8 x^{7}

- 2 cot (x + \frac{π}{4}) - 3

f (x) = \frac{1}{2 x}

What is the critical 6x^2-4x^4 ?
The critical 6x^2-4x^4 is x=-(sqrt(3))/2 ,x=0,x=(sqrt(3))/2