What is the inverse of f(x)=4x^2-8x+7 ?

The inverse of f(x)=4x^2-8x+7 is (2+sqrt(x-3))/2 ,(2-sqrt(x-3))/2

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inverse of f(x)=4x^2-8x+7

inverse

f (x) = 4 x^{2} - 8 x + 7

\frac{2 + x - 3}{2}, \frac{2 - x - 3}{2}

Solution steps

y = 4 x^{2} - 8 x + 7

Replace

x

with

y

x = 4 y^{2} - 8 y + 7

Solve for

y, x = 4 y^{2} - 8 y + 7

\frac{2 + x - 3}{2}, \frac{2 - x - 3}{2}

8 x + 2 y = 6

f (x) = \frac{x}{9 x - 7}

lo g_{6} (x - 1) - 5

f (x) = x^{2} - 36

cos (2 t)

What is the inverse of f(x)=4x^2-8x+7 ?
The inverse of f(x)=4x^2-8x+7 is (2+sqrt(x-3))/2 ,(2-sqrt(x-3))/2