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Popular >

midpoint (3,-3),(5,3)

Solution

midpoint

(3, - 3), (5, 3)

Solution

(4, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, - 3), (x_{2}, y_{2}) = (5, 3)

= (\frac{5 + 3}{2}, \frac{3 - 3}{2})

Refine

= (4, 0)

Popular Examples

domain of 2^x-2 domain

2^{x} - 2

critical f(x)=sqrt(x-3)critical points

f (x) = x - 3

line (0,42.4),(1,29.68)line

(0, 42.4), (1, 29.68)

inverse of f(x)= 2/3 x-8 inverse

f (x) = \frac{2}{3} x - 8

distance (-5,-2),(5,8)distance

(- 5, - 2), (5, 8)

Frequently Asked Questions (FAQ)

What is the midpoint (3,-3),(5,3) ?
The midpoint (3,-3),(5,3) is (4,0)