What is the inverse of f(x)=sqrt(x^2-2) ?

The inverse of f(x)=sqrt(x^2-2) is sqrt(x^2+2),-sqrt(x^2+2)

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inverse of f(x)=sqrt(x^2-2)

inverse

f (x) = x^{2} - 2

x^{2} + 2, - x^{2} + 2

Solution steps

y = x^{2} - 2

Replace

x

with

y

x = y^{2} - 2

Solve for

y, x = y^{2} - 2

x^{2} + 2, - x^{2} + 2

f (x) = 0.05 x + 15 + \frac{320}{x}

f (x) = x^{2} (5 - 4 x)^{2}

y = 4 x - 7, (0, - 6)

f (x) = ∣ x ∣

- lo g_{2} (x)

What is the inverse of f(x)=sqrt(x^2-2) ?
The inverse of f(x)=sqrt(x^2-2) is sqrt(x^2+2),-sqrt(x^2+2)