What is the inverse of f(x)=\sqrt[3]{1/3 (x+6)}+5 ?

The inverse of f(x)=\sqrt[3]{1/3 (x+6)}+5 is 3x^3-45x^2+225x-381

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{1/3 (x+6)}+5

inverse

f (x) = 3 \frac{1}{3} (x + 6) + 5

3 x^{3} - 45 x^{2} + 225 x - 381

Solution steps

y = 3 \frac{1}{3} (x + 6) + 5

Replace

x

with

y

x = 3 \frac{1}{3} (y + 6) + 5

Solve for

y, x = 3 \frac{1}{3} (y + 6) + 5

3 x^{3} - 45 x^{2} + 225 x - 381

(x + 1)^{\frac{4}{5}}

2 x^{2} + 16 x - 9

f (x) = 18 = 3 x

f (x) = x^{3} - \frac{3}{2} x^{2}

x^{2} - 7 x + 10

What is the inverse of f(x)=\sqrt[3]{1/3 (x+6)}+5 ?
The inverse of f(x)=\sqrt[3]{1/3 (x+6)}+5 is 3x^3-45x^2+225x-381