What is the perpendicular y= 2/3 x+c ?

The perpendicular y= 2/3 x+c is y=-3/2 x+b

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perpendicular y= 2/3 x+c

perpendicular

y = \frac{2}{3} x + c

y = - \frac{3}{2} x + b

Solution steps

Find the slope of

y = \frac{2}{3} x + c : m = \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{2}

Line with slope m=

- \frac{3}{2} : y = - \frac{3}{2} x + b

y = - \frac{3}{2} x + b

\frac{2 x ^{2} - 3}{x ^{2}}

(3, - 2), (13, 10)

f (x) = 3 x + y + 2 = 0

f (x) = - x + 2

f (x) = (2 - t)^{\frac{1}{6}}

What is the perpendicular y= 2/3 x+c ?
The perpendicular y= 2/3 x+c is y=-3/2 x+b