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Popular >

midpoint (8,-5),(2,3)

Solution

midpoint

(8, - 5), (2, 3)

Solution

(5, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (8, - 5), (x_{2}, y_{2}) = (2, 3)

= (\frac{2 + 8}{2}, \frac{3 - 5}{2})

Refine

= (5, - 1)

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inverse of f(x)=15-3x inverse

f (x) = 15 - 3 x

inverse of f(x)=((x+3))/2 inverse

f (x) = \frac{( x + 3 )}{2}

range of 2^{x-3}range

2^{x - 3}

domain of f(x)= 1/(sqrt(x^2-25))domain

f (x) = \frac{1}{x ^{2} - 25}

Frequently Asked Questions (FAQ)

What is the midpoint (8,-5),(2,3) ?
The midpoint (8,-5),(2,3) is (5,-1)