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Popular >

midpoint (3,-1),(7,-10)

Solution

midpoint

(3, - 1), (7, - 10)

Solution

(5, - \frac{11}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, - 1), (x_{2}, y_{2}) = (7, - 10)

= (\frac{7 + 3}{2}, \frac{- 10 - 1}{2})

Refine

= (5, - \frac{11}{2})

Popular Examples

asymptotes of f(x)=(6x^3-9x)/(2x^3-7x+5)asymptotes

f (x) = \frac{6 x ^{3} - 9 x}{2 x ^{3} - 7 x + 5}

parity f(x)=(e^x-1)/(e^x+1)parity

f (x) = \frac{e ^{x} - 1}{e ^{x} + 1}

inverse of f(x)=(3x+8)/(2x-3)inverse

f (x) = \frac{3 x + 8}{2 x - 3}

inverse of (x^2(x+1))/(x+1)inverse

\frac{x ^{2} ( x + 1 )}{x + 1}

parity x^3-5x parity

x^{3} - 5 x

Frequently Asked Questions (FAQ)

What is the midpoint (3,-1),(7,-10) ?
The midpoint (3,-1),(7,-10) is (5,-11/2)