What is the amplitude of-5sin(2x+pi/2) ?

The amplitude of-5sin(2x+pi/2) is 5

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amplitude of-5sin(2x+pi/2)

amplitude

- 5 sin (2 x + \frac{π}{2})

5

Solution steps

f (x) = - 5 sin (2 x + \frac{π}{2}), A = - 5

Therefore, the amplitude |A| is

5

5

f (x) = \frac{x - 3}{x - 5}

f (x) = \frac{x}{( x ^{2} + 1 ) ^{2}}

f (x) = x^{2} - 2 x^{3}

f (x) = - x^{2} + 10 x - 21

f (x) = \frac{3 - 3 x}{6 x - 1}