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Popular >

distance (5,-7),(0,3)

Solution

distance

(5, - 7), (0, 3)

Solution

55

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - 7)

and

(0, 3)

is

= (0 - 5)^{2} + (3 - (- 7))^{2}

Simplify

= 55

Popular Examples

intercepts of (-x^2+8)/(2x^2-3)intercepts

\frac{- x ^{2} + 8}{2 x ^{2} - 3}

perpendicular y= 5/3 x+5 perpendicular

y = \frac{5}{3} x + 5

domain of (9x^2-1)/(9x^3+6x^2+x)domain

\frac{9 x ^{2} - 1}{9 x ^{3} + 6 x ^{2} + x}

inverse of y= pi/4+sin(x)inverse

y = \frac{π}{4} + sin (x)

domain of sqrt(5x+20)domain

5 x + 20

Frequently Asked Questions (FAQ)

What is the distance (5,-7),(0,3) ?
The distance (5,-7),(0,3) is 5sqrt(5)