What is the perpendicular 3y=x-6,(2,-5) ?

The perpendicular 3y=x-6,(2,-5) is y=-3x+1

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perpendicular 3y=x-6,(2,-5)

perpendicular

3 y = x - 6, (2, - 5)

y = - 3 x + 1

Solution steps

Find the line

y = mx + b

perpendicular to

3 y = x - 6

that passes through

(2, - 5)

Find the slope of

3 y = x - 6 : m = \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = - 3

Find the line with slope m=

- 3

and passing through

(2, - 5) : y = - 3 x + 1

y = - 3 x + 1

(- 4, 1), (1, 7)

f (x) = \frac{1}{2} sec (\frac{π x}{2})

\frac{2 x ^{2} - 3 x - 20}{x - 5}

y = 0.25 x - 7, (- 6, 8)

f (x) = \frac{x ^{3} - 8}{x - 2}

What is the perpendicular 3y=x-6,(2,-5) ?
The perpendicular 3y=x-6,(2,-5) is y=-3x+1