What is the perpendicular 4x+5y=8,(4,-2) ?

The perpendicular 4x+5y=8,(4,-2) is y= 5/4 x-7

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perpendicular 4x+5y=8,(4,-2)

perpendicular

4 x + 5 y = 8, (4, - 2)

y = \frac{5}{4} x - 7

Solution steps

Find the line

y = mx + b

perpendicular to

4 x + 5 y = 8

that passes through

(4, - 2)

Find the slope of

4 x + 5 y = 8 : m = - \frac{4}{5}

Compute the slope of the perpendicular line:

m_{p} = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(4, - 2) : y = \frac{5}{4} x - 7

y = \frac{5}{4} x - 7

\frac{1}{x ^{2} - 7 x}

f (x) = x^{2} e^{- x^{2}}

f (x) = - 6 x^{3} + 9 x^{2} + 36 x

(- 2, - 6), (- 5, 0)

f (x) = 3 x^{4} + 12 x

What is the perpendicular 4x+5y=8,(4,-2) ?
The perpendicular 4x+5y=8,(4,-2) is y= 5/4 x-7