What is the critical f(x)=4x^3-18x^2+24x ?

The critical f(x)=4x^3-18x^2+24x is x=1,x=2

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critical f(x)=4x^3-18x^2+24x

critical points

f (x) = 4 x^{3} - 18 x^{2} + 24 x

x = 1, x = 2

Solution steps

4 x^{3} - 18 x^{2} + 24 x

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 2

Identify critical points not in

f (x)

domain

Domain of

4 x^{3} - 18 x^{2} + 24 x : - \infty < x < \infty

All critical points are in domain

x = 1, x = 2

f (x) = 15 - x

(5, 2), (- 4, - 3)

f (x) = \frac{4 x ^{2} + 2}{4 x + 4}

f (x) = \frac{3}{x + 2}

ln (x^{2} - 5 x + 6)

What is the critical f(x)=4x^3-18x^2+24x ?
The critical f(x)=4x^3-18x^2+24x is x=1,x=2