What is the inverse of f(x)=\sqrt[3]{4x-3} ?

The inverse of f(x)=\sqrt[3]{4x-3} is (x^3+3)/4

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inverse of f(x)=\sqrt[3]{4x-3}

inverse

\frac{x ^{3} + 3}{4}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} + 3}{4}

f (x) = (x + 4)^{2} - 9

4 x + 3

f (x) = x^{3} + 2 x^{2} - 3 x + 1

f (x) = \frac{x ^{2} - 25}{- 2 x ^{2} + 9 x + 5}

f (x) = \frac{x - 8}{x ^{2} + 14 x + 45}

What is the inverse of f(x)=\sqrt[3]{4x-3} ?
The inverse of f(x)=\sqrt[3]{4x-3} is (x^3+3)/4