What is the domain of 1/(sqrt(x^2-6x)) ?

The domain of 1/(sqrt(x^2-6x)) is x 6

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domain of 1/(sqrt(x^2-6x))

domain

\frac{1}{x ^{2} - 6 x}

x < 0 or x > 6

Interval Notation

(- \infty, 0) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 6

Find undefined (singularity) points:

x = 6, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 6

- 2 x + y = 4

\frac{x}{9 x - 8}

\frac{x ^{2} - 1}{1 + cos ^{2} ( x )}

f (x) = 3 x^{2} - 5

f (x) = 1 + 2 x

What is the domain of 1/(sqrt(x^2-6x)) ?
The domain of 1/(sqrt(x^2-6x)) is x<0\lor x>6