What is the domain of f(x)=sqrt(x^2-2x-8) ?

The domain of f(x)=sqrt(x^2-2x-8) is x = 4

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domain of f(x)=sqrt(x^2-2x-8)

domain

f (x) = x^{2} - 2 x - 8

x \leq - 2 or x \geq 4

Interval Notation

(- \infty, - 2] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 4

The function domain

x \leq - 2 or x \geq 4

\frac{4}{5} sin (- \frac{1}{3} x)

f (x) = x^{4} - 256

f (x) = 2 x^{2} - x + 2

f (x) = \frac{3 + x}{7 - x}

f (x) = 7 x - 5 x^{2}

What is the domain of f(x)=sqrt(x^2-2x-8) ?
The domain of f(x)=sqrt(x^2-2x-8) is x<=-2\lor x>= 4