What is the domain of sqrt(36-x^2)+sqrt(x+2) ?

The domain of sqrt(36-x^2)+sqrt(x+2) is -2<= x<= 6

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domain of sqrt(36-x^2)+sqrt(x+2)

domain

36 - x^{2} + x + 2

- 2 \leq x \leq 6

Interval Notation

[- 2, 6]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 6

The function domain

- 2 \leq x \leq 6

x^{3} - 1

f (x) = x + 2 \cdot \frac{x ^{2}}{x - 4}

2 y = 5

- 1 - 2

\frac{x ^{2} - 9}{x ^{2} - 4 x + 3}

What is the domain of sqrt(36-x^2)+sqrt(x+2) ?
The domain of sqrt(36-x^2)+sqrt(x+2) is -2<= x<= 6