What is the domain of f(x)=(8x)/(x^2-1) ?

The domain of f(x)=(8x)/(x^2-1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(8x)/(x^2-1)

domain

f (x) = \frac{8 x}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

g (x) = x^{2} - 5 x + 5

f (x) = - x - 8

f (x) = (x - 1)

\frac{5 - x}{x ^{2} - 3 x}

\frac{x ^{2} + x - 2}{x ^{2} - 1}

What is the domain of f(x)=(8x)/(x^2-1) ?
The domain of f(x)=(8x)/(x^2-1) is x<-1\lor-1<x<1\lor x>1