What is the parity y=(tan^2(3x^2-5))/((4x^2-3x)) ?

The parity y=(tan^2(3x^2-5))/((4x^2-3x)) is Neither even nor odd

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

parity y=(tan^2(3x^2-5))/((4x^2-3x))

parity

y = \frac{tan ^{2} ( 3 x ^{2} - 5 )}{( 4 x ^{2} - 3 x )}

Neither even nor odd

Solution steps

f (- x) : \frac{cos ^{2} ( 5 ) sin ^{2} ( 3 x ^{2} ) - cos ( 5 ) sin ( 5 ) sin ( 6 x ^{2} ) + sin ^{2} ( 5 ) cos ^{2} ( 3 x ^{2} )}{4 cos ^{2} ( 5 ) x ^{2} cos ^{2} ( 3 x ^{2} ) + 3 cos ^{2} ( 5 ) x cos ^{2} ( 3 x ^{2} ) + 4 cos ( 5 ) sin ( 5 ) x ^{2} sin ( 6 x ^{2} ) + 3 cos ( 5 ) sin ( 5 ) x sin ( 6 x ^{2} ) + 4 sin ^{2} ( 5 ) x ^{2} sin ^{2} ( 3 x ^{2} ) + 3 sin ^{2} ( 5 ) x sin ^{2} ( 3 x ^{2} )}

- f (x) : - \frac{tan ^{2} ( 3 x ^{2} - 5 )}{4 x ^{2} - 3 x}

Check parity of

\frac{tan ^{2} ( 3 x ^{2} - 5 )}{4 x ^{2} - 3 x}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

f (x) = \frac{2 x}{6 - x ^{2}}

(0) (4.2)

f (x) = - 6 x^{4} + 7 x^{2}

7 x + 3 y = 63

f (x) = x^{2} - 6 x + 10

What is the parity y=(tan^2(3x^2-5))/((4x^2-3x)) ?
The parity y=(tan^2(3x^2-5))/((4x^2-3x)) is Neither even nor odd