What is the inverse of f(x)=(x^5-10)^{1/3} ?

The inverse of f(x)=(x^5-10)^{1/3} is \sqrt[5]{x^3+10}

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inverse of f(x)=(x^5-10)^{1/3}

inverse

f (x) = (x^{5} - 10)^{\frac{1}{3}}

Solution steps

y = (x^{5} - 10)^{\frac{1}{3}}

Replace

x

with

y

x = (y^{5} - 10)^{\frac{1}{3}}

Solve for

y, x = (y^{5} - 10)^{\frac{1}{3}}

\frac{x ^{2} + 2 x}{x - 1}

(1.1) (7.9)

f (x) = \frac{x - 5}{x ^{2} - 11 x + 30}

4 x + 1

- 3 x + 1

What is the inverse of f(x)=(x^5-10)^{1/3} ?
The inverse of f(x)=(x^5-10)^{1/3} is \sqrt[5]{x^3+10}