What is the inverse of f(x)= 1/3 x^3-2 ?

The inverse of f(x)= 1/3 x^3-2 is cube root of 3x+6

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inverse of f(x)= 1/3 x^3-2

inverse

f (x) = \frac{1}{3} x^{3} - 2

Solution steps

y = \frac{1}{3} x^{3} - 2

Replace

x

with

y

x = \frac{1}{3} y^{3} - 2

Solve for

y, x = \frac{1}{3} y^{3} - 2

x^{2} - 6 x

3 + 2 sin (6 x + \frac{π}{4})

- 3 x^{2} + 3 x - 2

3 y + 6 x = 6

f (x) = 2 - lo g_{3} (x + 1)

What is the inverse of f(x)= 1/3 x^3-2 ?
The inverse of f(x)= 1/3 x^3-2 is cube root of 3x+6