What is the inverse of f(x)= 1/4 (x-2)^2 ?

The inverse of f(x)= 1/4 (x-2)^2 is 2sqrt(x)+2,-2sqrt(x)+2

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inverse of f(x)= 1/4 (x-2)^2

inverse

f (x) = \frac{1}{4} (x - 2)^{2}

2 x + 2, - 2 x + 2

Solution steps

y = \frac{1}{4} (x - 2)^{2}

Replace

x

with

y

x = \frac{1}{4} (y - 2)^{2}

Solve for

y, x = \frac{1}{4} (y - 2)^{2}

2 x + 2, - 2 x + 2

f (x) = - x^{2} + 36

\frac{1 - x ^{2}}{x ^{2} - 9}

f (x) = sin^{3} (x)

\frac{- 3 - 4 x + 25}{2}

f (x) = 2 x - 10

What is the inverse of f(x)= 1/4 (x-2)^2 ?
The inverse of f(x)= 1/4 (x-2)^2 is 2sqrt(x)+2,-2sqrt(x)+2