What is the critical (2x^2-5x+5)/(x-2) ?

The critical (2x^2-5x+5)/(x-2) is x=(4-sqrt(6))/2 ,x=(4+sqrt(6))/2

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critical (2x^2-5x+5)/(x-2)

critical points

\frac{2 x ^{2} - 5 x + 5}{x - 2}

x = \frac{4 - 6}{2}, x = \frac{4 + 6}{2}

Solution steps

\frac{2 x ^{2} - 5 x + 5}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{4 - 6}{2}, x = \frac{4 + 6}{2}, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x ^{2} - 5 x + 5}{x - 2} : x < 2 or x > 2

\frac{2 x ^{2} - 5 x + 5}{x - 2}

is not defined at

x = 2

, therefore:

x = \frac{4 - 6}{2}, x = \frac{4 + 6}{2}

cos (x) - 1

\frac{x}{- x - 2}

y = 1 - x^{2}

(- 6, \frac{5}{13}), (6, \frac{5}{13})

f (x) = ln (x) + 5

What is the critical (2x^2-5x+5)/(x-2) ?
The critical (2x^2-5x+5)/(x-2) is x=(4-sqrt(6))/2 ,x=(4+sqrt(6))/2