What is the range of f(x)= 3/(x+1) ?

The range of f(x)= 3/(x+1) is f(x) 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)= 3/(x+1)

range

f (x) = \frac{3}{x + 1}

f (x) < 0 or f (x) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{3}{x + 1}

Inverse of

\frac{3}{x + 1} : \frac{3}{x} - 1

\frac{3}{x} - 1

Find the domain of each inverse function

Domain of

\frac{3}{x} - 1 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

(2, - 9), (4, 1)

\frac{1}{2} (x - 1)^{3} + 3

f (x) = \frac{3 x - 4}{x ^{2} - 7 x + 12}

f (x) = \frac{( \frac{9}{x} )}{( \frac{9}{x} ) + 9}

- 2 x^{2} - 2 x - 2

What is the range of f(x)= 3/(x+1) ?
The range of f(x)= 3/(x+1) is f(x)<0\lor f(x)>0