What is the inverse of (2x)/(x^2+81) ?

The inverse of (2x)/(x^2+81) is (1+sqrt(-81x^2+1))/x ,(1-sqrt(-81x^2+1))/x

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inverse of (2x)/(x^2+81)

inverse

\frac{2 x}{x ^{2} + 81}

\frac{1 + - 81 x ^{2} + 1}{x}, \frac{1 - - 81 x ^{2} + 1}{x}

Solution steps

y = \frac{2 x}{x ^{2} + 81}

Replace

x

with

y

x = \frac{2 y}{y ^{2} + 81}

Solve for

y, x = \frac{2 y}{y ^{2} + 81}

\frac{1 + - 81 x ^{2} + 1}{x}, \frac{1 - - 81 x ^{2} + 1}{x}

\frac{3 x + 8}{2 x - 3}

lo g_{2} (x)

f (x) = \frac{1}{x + 2} - 1

f (x) = x^{3} + 3 x^{2} - 3

x^{2} + 4 x - 12

What is the inverse of (2x)/(x^2+81) ?
The inverse of (2x)/(x^2+81) is (1+sqrt(-81x^2+1))/x ,(1-sqrt(-81x^2+1))/x