What is the perpendicular y= 1/7 x+9,(2,5) ?

The perpendicular y= 1/7 x+9,(2,5) is y=-7x+19

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perpendicular y= 1/7 x+9,(2,5)

perpendicular

y = \frac{1}{7} x + 9, (2, 5)

y = - 7 x + 19

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{7} x + 9

that passes through

(2, 5)

Find the slope of

y = \frac{1}{7} x + 9 : m = \frac{1}{7}

Compute the slope of the perpendicular line:

m_{p} = - 7

Find the line with slope m=

- 7

and passing through

(2, 5) : y = - 7 x + 19

y = - 7 x + 19

f (x) = 3 x - 4 y = - 8

f (x) = 1.5 (2)^{x}

f (x) = \frac{x - 1}{( x + 2 ) ( x - 3 )}

f (x) = sin (7 x)

f (x) = \frac{7}{2} x - \frac{25}{2}

What is the perpendicular y= 1/7 x+9,(2,5) ?
The perpendicular y= 1/7 x+9,(2,5) is y=-7x+19