What is the range of f(x)=sqrt(x+2) ?

The range of f(x)=sqrt(x+2) is f(x)>= 0

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range of f(x)=sqrt(x+2)

range

f (x) = x + 2

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

(4, 3), (0, 3)

f (x) = 4 x^{3} - 7

5 x - 2 y = 8

\frac{2 x ^{2} + x - 1}{3 x ^{2} - 11 x - 4}

(0, 5), (6, 0)