What is the domain of f(x)=(sqrt(81-x^2))/(x^2-9)=y ?

The domain of f(x)=(sqrt(81-x^2))/(x^2-9)=y is -infinity <y<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(81-x^2))/(x^2-9)=y

domain

f (x) = \frac{81 - x ^{2}}{x ^{2} - 9} = y

- \infty < y < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < y < \infty

f (x) = \frac{3 x}{5 + x ^{2}}

y = 5 x + 6 x^{2}

f (x) = e^{8 x - 9}

f (x) = \frac{x - 2}{x + 3}

f (x) = e^{- 2 x^{2}}

What is the domain of f(x)=(sqrt(81-x^2))/(x^2-9)=y ?
The domain of f(x)=(sqrt(81-x^2))/(x^2-9)=y is -infinity <y<infinity