What is the critical f(x)=x(x-2) ?

The critical f(x)=x(x-2) is x=1

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critical f(x)=x(x-2)

critical points

f (x) = x (x - 2)

x = 1

Solution steps

x (x - 2)

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

x (x - 2) : - \infty < x < \infty

All critical points are in domain

x = 1

\frac{x - 4}{x + 4}

∣ x - 2 ∣ + 3

f (x) = (x + 2) 3

f (x) = - 6 x^{2}

f (x) = - \frac{3}{( x + 8 )}