What is the inverse of f(x)=(x+2)^2,x>=-2 ?

The inverse of f(x)=(x+2)^2,x>=-2 is sqrt(x)-2,-sqrt(x)-2

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inverse of f(x)=(x+2)^2,x>=-2

inverse

f (x) = (x + 2)^{2}, x \geq - 2

x - 2, - x - 2

Solution steps

y = (x + 2)^{2}

Replace

x

with

y

x = (y + 2)^{2}

Solve for

y, x = (y + 2)^{2}

x - 2, - x - 2

y - 4 = \frac{1}{4} (x + 8)

x^{2} + 3 x + 3

y = 3 x^{3} - 16 x + 2

h (x) = - x + 3

f (x) = e^{- x}

What is the inverse of f(x)=(x+2)^2,x>=-2 ?
The inverse of f(x)=(x+2)^2,x>=-2 is sqrt(x)-2,-sqrt(x)-2