What is the extreme f(x)=-1/3 x^3+x-12 ?

The extreme f(x)=-1/3 x^3+x-12 is Minimum(-1,-38/3),Maximum(1,-34/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-1/3 x^3+x-12

extreme points

f (x) = - \frac{1}{3} x^{3} + x - 12

Minimum (- 1, - \frac{38}{3}), Maximum (1, - \frac{34}{3})

Solution steps

f^{'} (x) = - x^{2} + 1

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- \frac{1}{3} x^{3} + x - 12 : - \frac{38}{3}

Minimum (- 1, - \frac{38}{3})

Plug

x = 1

into

- \frac{1}{3} x^{3} + x - 12 : - \frac{34}{3}

Maximum (1, - \frac{34}{3})

Minimum (- 1, - \frac{38}{3}), Maximum (1, - \frac{34}{3})

13 x - 11 y = - 12

f (x) = \frac{x ^{2} - 6 x + 9}{x ^{2} + x - 2}

y = \frac{x ^{2} + x - 6}{x ^{2} - 7 x + 10}

y = x - 1

2 x

What is the extreme f(x)=-1/3 x^3+x-12 ?
The extreme f(x)=-1/3 x^3+x-12 is Minimum(-1,-38/3),Maximum(1,-34/3)