What is the range of f(x)=-(1/3)^x+3 ?

The range of f(x)=-(1/3)^x+3 is f(x)<3

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range of f(x)=-(1/3)^x+3

range

f (x) = - (\frac{1}{3})^{x} + 3

f (x) < 3

Interval Notation

(- \infty, 3)

Solution steps

The range of an exponential function of the form

- c \cdot n^{a x + b} + k

f (x) < k

k = 3

f (x) < 3

f (x) = \frac{( x + 5 )}{x - 2}

- x + 2 y - 10 = 0

tan (x + π)

f (x) = \frac{- 9 x - 36}{3 x - 9}

\frac{x}{x ^{2} + 25}