What is the inverse of \sqrt[5]{x}-2 ?

The inverse of \sqrt[5]{x}-2 is x^5+10x^4+40x^3+80x^2+80x+32

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inverse of \sqrt[5]{x}-2

inverse

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 32

Solution steps

Replace

x

with

y

Solve for

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 32

10

f (x) = (x - 6)

f (x) = \frac{1}{x + 3} + 2

3 x + 12

f (x) = - x^{2} + 3 x, - 1 \leq x \leq 3

What is the inverse of \sqrt[5]{x}-2 ?
The inverse of \sqrt[5]{x}-2 is x^5+10x^4+40x^3+80x^2+80x+32