What is the domain of f(x)=(x^2+1)/x ?

The domain of f(x)=(x^2+1)/x is x 0

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domain of f(x)=(x^2+1)/x

domain

f (x) = \frac{x ^{2} + 1}{x}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

\frac{x ^{2} - x - 6}{x - 2}

f (x) = \frac{x - 1}{x}

\frac{1}{6 x - 12} 2 x + 16

f (x) = 4 x^{2} - 2 x, (1, 4)

(0, 8), (4, 0)

What is the domain of f(x)=(x^2+1)/x ?
The domain of f(x)=(x^2+1)/x is x<0\lor x>0