What is the perpendicular 4x+5y=7,(4,-3) ?

The perpendicular 4x+5y=7,(4,-3) is y= 5/4 x-8

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perpendicular 4x+5y=7,(4,-3)

perpendicular

4 x + 5 y = 7, (4, - 3)

y = \frac{5}{4} x - 8

Solution steps

Find the line

y = mx + b

perpendicular to

4 x + 5 y = 7

that passes through

(4, - 3)

Find the slope of

4 x + 5 y = 7 : m = - \frac{4}{5}

Compute the slope of the perpendicular line:

m_{p} = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(4, - 3) : y = \frac{5}{4} x - 8

y = \frac{5}{4} x - 8

(- 4, 2), (4, 0)

f (x) = \frac{x - 3}{x ^{2} - 16}

f (x) = \frac{x - 1}{x + 3}

x^{2} (x - 10)^{3}

f (x) = cos (5 x) + 3 sin (5 x)

What is the perpendicular 4x+5y=7,(4,-3) ?
The perpendicular 4x+5y=7,(4,-3) is y= 5/4 x-8