What is the critical f(x)=(x-1)^{4/5} ?

The critical f(x)=(x-1)^{4/5} is x=1

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critical f(x)=(x-1)^{4/5}

critical points

f (x) = (x - 1)^{\frac{4}{5}}

x = 1

Solution steps

(x - 1)^{\frac{4}{5}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

(x - 1)^{\frac{4}{5}} : - \infty < x < \infty

All critical points are in domain

x = 1

f (x) = ln (x^{2} - 4)

f (x) = x^{2} + 6 x + 4

x^{2} - 7 x

f (x) = \frac{1}{4} (x + 3)^{2} - 5

x^{2} + 12 x = - 36