What is the range of log_{2}(1/(2^{-1/2)}) ?

The range of log_{2}(1/(2^{-1/2)}) is f(x)= 1/2

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range of log_{2}(1/(2^{-1/2)})

range

lo g_{2} (\frac{1}{2 ^{- \frac{1}{2}}})

f (x) = \frac{1}{2}

Decimal Notation

f (x) = 0.5

Solution steps

Simplify

lo g_{2} (\frac{1}{2 ^{- \frac{1}{2}}}) : \frac{1}{2}

The range of constant function

f (x) = a

is constant

a

f (x) = \frac{1}{2}

x^{2} y - 9 y - 3 x^{2} = 0

f (x) = - x^{2} + 8

f (x) = (x + 5)^{\frac{2}{3}}

x^{2} - 6

f (x) = \frac{2 x - 1}{6 - 5 x}

What is the range of log_{2}(1/(2^{-1/2)}) ?
The range of log_{2}(1/(2^{-1/2)}) is f(x)= 1/2