What is the inverse of \sqrt[3]{4x}-3 ?

The inverse of \sqrt[3]{4x}-3 is (x^3+9x^2+27x+27)/4

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inverse of \sqrt[3]{4x}-3

inverse

\frac{x ^{3} + 9 x ^{2} + 27 x + 27}{4}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} + 9 x ^{2} + 27 x + 27}{4}

\frac{( x + 6 )}{( x ^{2} + 3 x - 4 )}

f (x) = \frac{x}{8} + 3

f (x) = x^{2} - 12 x + 27

y = \frac{3}{4} x + 1

f (x) = 8 x^{3} + 5

What is the inverse of \sqrt[3]{4x}-3 ?
The inverse of \sqrt[3]{4x}-3 is (x^3+9x^2+27x+27)/4