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Popular >

range of f(x)=2x^2-8x+9

Solution

range

f (x) = 2 x^{2} - 8 x + 9

Solution

f (x) \geq 1

+1

Interval Notation

[1, \infty)

Solution steps

Vertex of

2 x^{2} - 8 x + 9 :

Minimum

(2, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (2, 1)

f (x) \geq 1

Popular Examples

range of x^2-4x-21 range

x^{2} - 4 x - 21

domain of sqrt(x)+sqrt(1-x)domain

x + 1 - x

asymptotes of f(x)= 1/2 \sqrt[4]{x}asymptotes

inverse of f(x)=sqrt(2x-5)inverse

f (x) = 2 x - 5

intercepts of f(x)=2x^3-1 intercepts

f (x) = 2 x^{3} - 1

Frequently Asked Questions (FAQ)

What is the range of f(x)=2x^2-8x+9 ?
The range of f(x)=2x^2-8x+9 is f(x)>= 1