What is the domain of f(x)=(sqrt(x-4))^2-1 ?

The domain of f(x)=(sqrt(x-4))^2-1 is x>= 4

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domain of f(x)=(sqrt(x-4))^2-1

domain

f (x) = (x - 4)^{2} - 1

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

The function domain

x \geq 4

f (x) = - 35 x + 5

f (x) = t 4 - t, t < 3

\frac{1}{x - 2}

- x + 4

f (x) = \frac{2 x}{5 - 3 x}

What is the domain of f(x)=(sqrt(x-4))^2-1 ?
The domain of f(x)=(sqrt(x-4))^2-1 is x>= 4